400-101 Guide

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  • Cisco
  • Exam Number/Code 400-101
  • Product Name CCIE Routing and Switching (v5.0)
  • Questions and Answers
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2017 Apr 400-101 test questions

Q491. Which two statements about TCP are true? (Choose two.) 

A. TCP option must be divisible by 32. 

B. It has a 16-bit window size. 

C. Its maximum data offset is fifteen 32-bit words. 

D. It has a 32-bit window size. 

E. Its maximum data offset is ten 32-bit words. 

F. It has a 32-bit checksum field. 

Answer: B,C 


Q492. You are implementing new addressing with EIGRP routing and must use secondary addresses, which are missing from the routing table. Which action is the most efficient solution to the problem? 

A. Disable split-horizon on the interfaces with secondary addresses. 

B. Disable split-horizon inside the EIGRP process on the router with the secondary interface addresses. 

C. Add additional router interfaces and move the secondary addresses to the new interfaces. 

D. Use a different routing protocol and redistribute the routes between EIGRP and the new protocol. 

Answer:

Explanation: 

Normally, routers that are connected to broadcast-type IP networks and that use distance-vector routing protocols employ the split horizon mechanism to reduce the possibility of routing loops. Split horizon blocks information about routes from being advertised by a router out of any interface from which that information originated. This behavior usually optimizes communications among multiple routers, particularly when links are broken. However, with nonbroadcast networks, situations can arise for which this behavior is less than ideal. For these situations, you might want to disable split horizon with EIGRP and RIP. If an interface is configured with secondary IP addresses and split horizon is enabled, updates might not be sourced by every secondary address. One routing update is sourced per network number unless split horizon is disabled. 

Reference: 

http://www.cisco.com/c/en/us/td/docs/ios/12_2/ip/configuration/guide/fipr_c/1cfrip.html 


Q493. What is the function of an EIGRP sequence TLV packet? 

A. to acknowledge a set of sequence numbers during the startup update process 

B. to list the peers that should listen to the next multicast packet during the reliable multicast process 

C. to list the peers that should not listen to the next multicast packet during the reliable multicast process 

D. to define the initial sequence number when bringing up a new peer 

Answer:

Explanation: 

EIGRP sends updates and other information between routers using multicast packets to 224.0.0.10. For example in the topology below, R1 made a change in the topology and it needs to send updates to R2 & R3. It sends multicast packets to EIGRP multicast address 224.0.0.10. Both R2 & R3 can receive the updates and acknowledge back to R1 using unicast. Simple, right? But what if R1 sends out updates, only R2 replies but R3 never does? In the case a router sends out a multicast packet that must be reliable delivered (like in this case), an EIGRP process will wait until the RTO (retransmission timeout) period has passed before beginning a recovery action. This period is calculated from the SRTT (smooth round-trip time). After R1 sends out updates it will wait for this period to expire. Then it makes a list of all the neighbors from which it did not receive an Acknowledgement (ACK). Next it sends out a packet telling these routers stop listening to multicast until they are been notified that it is safe again. Finally the router will begin sending unicast packets with the information to the routers that didn’t answer, continuing until they are caught up. In our example the process will be like this: 

1. R1 sends out updates to 224.0.0.10 

2. R2 responds but R3 does not 

3. R1 waits for the RTO period to expire 

4. R1 then sends out an unreliable-multicast packet, called a sequence TLV (Type-Length-Value) packet, which tells R3 not to listen to multicast packets any more 

5. R1 continues sending any other muticast traffic it has and delivering all traffic, using unicast to R3, until it acknowledges all the packets 

6. Once R3 has caught up, R1 will send another sequence TLV, telling R3 to begin listening to multicast again. The sequence TLV packet contains a list of the nodes that should not listen to multicast packets while the recovery takes place. But notice that the TLV packet in step 6 does not contain any nodes in the list. 

Note. In the case R3 still does not reply in step 4, R1 will attempt to retransmit the unicast 16 times or continue to retransmit until the hold time for the neighbor in question expires. After this time, R1 will declare a retransmission limit exceeded error and will reset the neighbor. 

(Reference: EIGRP for IP: Basic Operation and Configuration) 


Q494. Refer to the exhibit. 

Which feature can R1 use to fail over from R2 to R3 if the address for R2 becomes unavailable? 

A. object tracking 

B. HSRP 

C. GLBP 

D. LACP 

Answer:

Explanation: 

The object tracking feature allows you to create a tracked object that multiple clients can use to modify the client behavior when a tracked object changes. Several clients register their interest with the tracking process, track the same object, and take different actions when the object state changes. 

Clients include the following features: 

. Embedded Event Manager (EEM) 

. Gateway Load Balancing Protocol (GLBP) 

. Hot Standby Redundancy Protocol (HSRP) 

. Virtual port channel (vPC) 

. Virtual Router Redundancy Protocol (VRRP) 

The object tracking monitors the status of the tracked objects and communicates any changes made to interested clients. Each tracked object is identified by a unique number that clients can use to configure the action to take when a tracked object changes state. 

Reference: http://www.cisco.com/c/en/us/td/docs/switches/datacenter/sw/5_x/nx-os/unicast/configuration/guide/l3_cli_nxos/l3_object.html 


Leading 400-101 test:

Q495. Which three statements about the default behaviour of eBGP sessions are true? (Choose three.) 

A. eBGP sessions between sub-ASs in different confederations transmit the next hop unchanged. 

B. The next hop in an eBGP peering is the IP address of the neighbor that announced the route. 

C. When a route reflector reflects a route to a client, it transmits the next hop unchanged. 

D. The next hop in an eBGP peering is the loopback address of the interface that originated the route. 

E. The next hop in an eBGP peering is the loopback address of the neighbor that announced the route. 

F. When a route reflector reflects a route to a client, it changes the next hop to its own address. 

Answer: A,B,C 


Q496. When you enable the MPLS Multi-VRF feature, which two supported routing protocols can be used to exchange routing information between PE routers and CE routers? (Choose two.) 

A. BGP 

B. RIP 

C. OSPF 

D. EIGRP 

E. IS-IS 

Answer: A,B 


Q497. DRAG DROP 

Drag and drop the IGMPv2 timer on the left to its default value on the right. 

Answer: 


Q498. Which two methods change the IP MTU value for an interface? (Choose two.) 

A. Configure the default MTU. 

B. Configure the IP system MTU. 

C. Configure the interface MTU. 

D. Configure the interface IP MTU. 

Answer: C,D 

Explanation: 

An IOS device configured for IP+MPLS routing uses three different Maximum Transmission Unit (MTU) values: The hardware MTU configured with the mtu interface configuration command 

. The IP MTU configured with the ip mtu interface configuration command 

. The MPLS MTU configured with the mpls mtu interface configuration command 

The hardware MTU specifies the maximum packet length the interface can support … or at least that's the theory behind it. In reality, longer packets can be sent (assuming the hardware interface chipset doesn't complain); therefore you can configure MPLS MTU to be larger than the interface MTU and still have a working network. Oversized packets might not be received correctly if the interface uses fixed-length buffers; platforms with scatter/gather architecture (also called particle buffers) usually survive incoming oversized packets. 

IP MTU is used to determine whether am IP packet forwarded through an interface has to be fragmented. It has to be lower or equal to hardware MTU (and this limitation is enforced). If it equals the HW MTU, its value does not appear in the running configuration and it tracks the changes in HW MTU. For example, if you configure ip mtu 1300 on a Serial interface, it will appear in the running configuration as long as the hardware MTU is not equal to 1300 (and will not change as the HW MTU changes). However, as soon as the mtu 1300 is configured, the ip mtu 1300 command disappears from the configuration and the IP MTU yet again tracks the HW MTU. 

Reference: http://blog.ipspace.net/2007/10/tale-of-three-mtus.html 


Q499. What are the three variants of NTPv4? (Choose three.) 

A. client/server 

B. broadcast 

C. symmetric 

D. multicast 

E. asymmetric 

F. unicast 

Answer: A,B,C 


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